(2x-7)^5/(2x-7)^3

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Solution for (2x-7)^5/(2x-7)^3 equation: 


D( x )

(2*x-7)^3 = 0

(2*x-7)^3 = 0

(2*x-7)^3 = 0

2*x-7 = 0 // + 7

2*x = 7 // : 2

x = 7/2

x in (-oo:7/2) U (7/2:+oo)

((2*x-7)^5)/((2*x-7)^3) = 0

(2*x-7)^2 = 0

2*x-7 = 0 // + 7

2*x = 7 // : 2

x = 7/2

x in { 7/2} 

x belongs to the empty set

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